80 Extractio de \({1 \over 3}\) 12 de \({3 \over 4}\) 126¹⁶⁰

Verum si \({1 \over 3}\) 12 de \({3 \over 4}\) 126 extrahere volueris, describes questionem ut supra et

1521 148 \({3 \over 4}\) 126 \({1 \over 3}\) 12 residuum extractionis \({5 \over 12}\) 114

¹⁶¹ reperies prescripta 148 et 1521, et¹⁶² extrahes 148 de 1521; remanebunt duodecime 1373, quas¹⁶³ divide suprascripta ratione per 12, exibunt integra \({5 \over 12}\) 114 pro residuo dicte extractionis, ut in questione ostenditur.

81 Vel aliter: extrahe integra de integris, videlicet 12 de 126; remanent 114. Deinde extrahe \({1 \over 3}\) de \({3 \over 4}\); remanent \({5 \over 12}\), quas adde cum 114; erunt \({5 \over 12}\) 114 similiter.

82 Et si dividere volueris \({3 \over 4}\) 126 per \({1 \over 3}\) 12, divides 1521 per regulam de 148¹⁶⁴,

1521 148 \({3 \over 4}\) 126 \({1 \over 3}\) 12 divisio maioris per minorem \({1~~10 \over 4~~37}\) 10

¹⁶⁵ que est \({1~~0\phantom{7} \over 4~~37}\), exibunt \({1~~10 \over 4~~37}\) 10 pro quesita divisione, ut in sua demonstratur descriptione¹⁶⁶.

83 Item si¹⁶⁷ minorem per maiorem dividere volueris, scilicet \({1 \over 3}\) 12 per \({3 \over 4}\) 126¹⁶⁸,

1521 148 \({3 \over 4}\) 126 \({1 \over 3}\) 12 divisio minoris per maiorem \({4~~3\phantom{3}~~1\phantom{3} \over 9~~13~~13}\)

¹⁶⁹ repertis quidem 148 et 1521, divides 148 per regulam de 1521, que est \({1~~0\phantom{3}~~0\phantom{3} \over 9~~13~~13}\); exibit \({4~~3\phantom{3}~~1\phantom{3} \over 9~~13~~13}\) unius¹⁷⁰ integri pro quesita divisione.